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Mathematics 12 Online
OpenStudy (brelove13):

find the value of a, given that the maximum value of the function f(x)=ax^2+3x+4 is 5.

OpenStudy (anonymous):

Take the derivative and set it to 5 f'(x) = 2ax + 3 = 5 Solve for a.

OpenStudy (brelove13):

i'm confused

OpenStudy (brelove13):

find the value of a, given that the maximum value of the function \[ax ^{2}+3x+4\] is 5.

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