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no should be 1/4 a^2 exponent is negative
@FaiqRaees PLEASE check my answer :)
It should be a^2 / 4
If you want to know why let me know
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yes can you show me the steps as well @FaiqRaees
\[\large\rm {8a^{-3}}^{-2/3} \]\[\large\rm 8^{-2/3} * {a^{-3}}^{-2/3} \]\[\large\rm \frac{1}{4}*a^{-3*\frac{-2}{3}} \]\[\large\rm \frac{1}{4}*a^2\]\[\large\rm \frac{a^2}{4}\]
If you still couldn't understand let me know
Ok I see what to do, Thanks a lot @FaiqRaees ! :)
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