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Let g(x)=5x-2 and h(x)=x^2+1. Find the value of the expression. (h o g)(-1)
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@phi @welshfella
the (h o g)(-1) means first do g(-1) then put that number into h if you replace x with -1, what is 5x-2 ?
-7!
first, in g(x) = 5*x-2 put in -1 you get 5*-1 - 2 which is -5 - 2 or -7 yes -7
now do h(-7) that means put -7 in for x in x^2 + 1 what do you get ?
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-48?
what is -7 * -7 ?
49+1=50?
yes, the answer is 50
Thank you!(:
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yw
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