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Solve 4^(2x) = 7^(x−1). 2.35389 −2.35389 −1 1
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@peachpi
do you have to do this by hand?
nope
i can use a calculator and stuff
you'd have to take a log of both sides. then rewrite ln (4^(2x)) = ln (7^(x-1)) 2x ln 4 = (x - 1) ln 7
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oh if you can use a calculator, use wolfram alpha. or graph both sides and find the intersection point
ok thanks!!! I have one more and I am really confudes... I will medal you and everything :-) thanks so much for the help so far
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