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Algebra
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8 < x(7 – x)
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are you supposed to solve for \(x\)?
yes
this is way harder than the others first multiply out on the right to get \[8<7x-x^2\]
then add \(x^2\) and subtract \(7x\) to get \[x^2-7x+8<0\]
ok
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is there a typo somewhere in the question? you have to solve this using the quadratic formula are you sure it is not \[-8<x(x-7)\]?
I'm sure
are you just supposed to find some number that works? what does the question actually say?
They're two questions. 1. What is the solution of the inequality? 2. Solve for x
Cymath.com might be able to help you.
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