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Physics 13 Online
OpenStudy (ayonnaleflore):

will fan and medal

OpenStudy (ayonnaleflore):

A force of 100.0 N acts in a direction at an angle of 45.0° with the x-axis. What is the magnitude of the x component of the force? 50.0 N 70.7 N 145 N 0.00 N

OpenStudy (priyar):

Actually you can resolve any vector (here Force ) like this: |dw:1457192401570:dw|

OpenStudy (priyar):

here they are asking for the x component of the force.. so u take the comp. along x axis which is FCos (theta).. Here theta = 45 degrees and F=100.. so x comp. = 100cos (45) =?

OpenStudy (priyar):

So which option is it ? @ayonnaleflore

OpenStudy (michele_laino):

here we have to do this computation: \[\huge {F_x} = F\cos 45 = \frac{{100}}{{\sqrt 2 }} = ...?\]

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