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A simple pendulum is 5 m long. What is the period of small oscillations for this pendulum if it is located in an elevator (a) Standing still? (b) Moving upwards with constant velocity of 7.45 m/s? (c) Accelerating upward at 5 m/s2? (d) Accelerating downward at 5 m/s2?
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if the oscillations are small, it will undergo SHM .. so time period(T) is given by: \[T = 2\pi \sqrt{\frac{ l }{ g }}\] where l-length and g- gravitational acceleration..
l is constant and is equal to 5m. So decide how g will change in each case..
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