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Solve sinx + cosx = 1 on 0 X 2 pi
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square both sides, what do you get?
sin^2(X) +2sin(x)cos(x)+ cos^2(x) =1
ohhh 1+sin(2x) =1
ohhh no
don't go that way, 2sinx cosx =0 then either sinx =0 or cos x =0. solve for them.
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oh got it , so its's 0 and pi/2?
pi/2, pi, 3pi/2,
on your problem \(0\leq x\leq 2\pi\) or just \(0<x<2\pi\)?
equal or not?
0≤x≤2π
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ok, so take 0 and 2pi also
|dw:1457139876314:dw|
oh got it, thanks! :)
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