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OpenStudy (fifib):

Given the reaction: Cu^2+(aq) + S^2-(aq) = CuS (s) what will happen (a) CuSO4 is added and (b) if Na2SO4 is added? A. (a) nothing (b) less product will form B. (a) more product will form (b) nothing C. (a) nothing (b) more product will form D. (a) less product will form (b) nothing

OpenStudy (fifib):

It is a reversible equation. @Photon336 Help? I will be right back

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