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Math help. PLS help.
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@hartnn
can you find sin (7pi/6) ?? hint: sin x = - sin(pi -x)
how is sin negative?
oops, sin x = sin (pi -x)
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you can take x = 7pi/6 here
what is pi-x?
\(\pi -x\)
isnt 7pi/6 = 1/2?
sin 7pi/6 is -1/2 not +1/2
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then just square both sides
why is 7pi/6 = -1/2??
\(\sin 7\pi/6 = \sin (\pi -7\pi/6) = \sin(-\pi/6) = -\sin(\pi/6) = -1/2\)
i dont get it
you keep on saying 7pi/6 = 1/2... note that 7pi/6 is an angle, 1/2 is a number. we can't equate them. sin 7pi/6 is a number which is = -1/2 as i have shown
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we have used this property \(\sin x = \sin (\pi -x)\) and just plug in x = 7pi/6 therwe
ohh ok what about cos then?
@hartnn
you mean cos 7pi/6?
the formula for finding the value for cos
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