Find the zeros for the polynomial function and give the multiplicity for each zero. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each zero. f(x)=2(x+1)(x-7)^2 the (x-7) is squared please help
The zero are the root of the equation and the multiplicity is the power that is its corresponding factor raised to. For example, in the polynomial function f(x) = (x – 3)^4(x – 5)(x – 8)^2, the zero 3 has multiplicity 4, 5 has multiplicity 1, and 8 has multiplicity 2. Although this polynomial has only three zeros, we say that it has seven zeros counting multiplicity.
Can you work the zeroes and the multiplicity of your problem now
(x + 1) is one of the factors so if we put this = 0 we find one of the roots(zeroes) x + 1 = 0 so x = what?
can you solve that simple equation
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