Question

A force of 50 pounds stretches a spring
3 inches.
(a) How far will a force of 20 pounds stretch
the spring?
(b) What force is required to stretch the spring
1.5 inches?

Answer 1

Hooke's law says that F=kx

Answer 2

So what would f, k, and x represent?

Answer 3

force, hooke constant, and distance

Answer 4

we can use a modified form of hooke law: F1/F2=x1/x2

Answer 5

F1=50,F2=20,x1=3, can you solve for x2?

Answer 6

Would x2=1.19?

Answer 7

good!