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A force of 50 pounds stretches a spring 3 inches. (a) How far will a force of 20 pounds stretch the spring? (b) What force is required to stretch the spring 1.5 inches?
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Hooke's law says that F=kx
So what would f, k, and x represent?
force, hooke constant, and distance
we can use a modified form of hooke law: F1/F2=x1/x2
F1=50,F2=20,x1=3, can you solve for x2?
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Would x2=1.19?
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