John is building a laundry in the basement of the apartment building he owns. He wants the width of the room to be 20 feet and the length to be longer than the width. He wants the area of the room to be more than 600 ft^2.
Write and solve an inequality to represent this situation.
What could be the length?
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jimthompson5910 (jim_thompson5910):
|dw:1457311836517:dw|
OpenStudy (anonymous):
Yes!
jimthompson5910 (jim_thompson5910):
area of rectangle = length*width
A = L*W
A = x*20
A = 20*x
the area expression is 20x
we want the area to be larger than 600 sq ft, so we want A > 600
jimthompson5910 (jim_thompson5910):
A > 600
20x > 600 ... replace A with 20x (since the two are equivalent)
I'll let you solve for x
OpenStudy (anonymous):
OMG, thank you!!!
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jimthompson5910 (jim_thompson5910):
tell me what you get
OpenStudy (anonymous):
ok, x=4?
jimthompson5910 (jim_thompson5910):
to solve `20x > 600` for x, we need to divide both sides by 20
20x means 20 times x
we undo the multiplication through division
OpenStudy (anonymous):
oh!
jimthompson5910 (jim_thompson5910):
|dw:1457312037041:dw|
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