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MIT 18.03SC Differential Equations
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find the value of m such that the function y=e^mx is asolution of y`+2y=0
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Just plug in the function, like this: (e^mx)' = me^mx me^mx + 2e^mx = 0 since e^mx is never 0, we got: m + 2 = 0 therefore m = -1.
alieeeeeen true though supposed to be m = -2
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