Question

Inverse Trigonometric Functions? Help with 2 practice problems?

Answer 1

@jhonyy9

Answer 2

Triangles are your best friend

Answer 3

The first is cosine. What is that in relation to opposite, adjacent, and hypotenuse?

Answer 4

Hold on... for #6 i got \[\arccos (-\frac{ \sqrt{2} }{ 2 }) = \frac{ 3\pi }{ 4 }\] and \[\arcsin (-\frac{ \sqrt{-2} }{ 2 }) = -\frac{ \pi }{ 4 }\]

Answer 5

I was thinking pi/4, but the negitave. both of those are the same value. Looks good to me actually

Answer 6

Okay thank you! I'm trying to find the opposite, adjacent, and hypotenuse.. I have to go in a few minutes tho.