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OpenStudy (anonymous):
factor 4x^2x-3 by multiplying the distributive property
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OpenStudy (anonymous):
who ever helps me gets a medal
OpenStudy (photon336):
Is this your question? \[4x^{2}(x-3)\]
OpenStudy (anonymous):
\[4x^2 + 4x-3\]
OpenStudy (photon336):
(2x-1)(2x+3)
OpenStudy (anonymous):
thank you
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OpenStudy (photon336):
because when you think about it you have to foil (2x-1)(2x+3) = (4x^{2})+6x-2x-3) = 4x^{2}+4x-3
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