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Can someone help me with DEPRECATED Trigonometry? I think I found out how to solve those angular problems, but I'm not quite sure
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Sin = opposite over hypotenuse, correct? so it would be AC over AB?
you are right
i have never heard of "depreciated" trigonometry before what does that mean?
Oh.. it was just the name on the course... I go through khan academy when I'm having a bit of struggle on the course... https://www.khanacademy.org/partner-content/nasa/measuringuniverse/measure_the_solarsystem/a/a-flat-earth
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What's the numerical value of your "AC over AB?"
I got \[5 \over 13\] because the opposite was AC = 5 and my adjacent was BC = 12
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