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Using the digits 9,8,7,6 and 5 exactly once, two numbers N1 and N2 are formed such that their product is the maximum possible number.Find the sum of N1 and N2. (a.971 b.863 c.962 d.1052)
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it is d , n1=987 n2=65
yes D is the answer..could you please tell me what did you do ?
just the product woul be maximum if you had those numbers
but if we take 867 and 95 the product of this is 82365 which is greater than the product of 987 and 65...so how can we conclude that the numbers vre 987 and 65 ?
also 85 and 967 the product is 82195 which is greater than the product of 987 and 65
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