There are three consecutive natural numbers. The middle number was cubed , the least was squared and the greatest was raised to its first power. The sum of the results was tripled and then it's square root was found. The value obtained was observed to be equal to the sum of the original numbers. The least of the original numbers is L . which of the following can be concluded ? A. L is greater than or equal to 16
B.12

Question

There are three consecutive natural numbers. The middle number was cubed , the least was squared and the greatest was raised to its first power. The sum of the results was tripled and then it's square root was found. The value obtained was observed to be equal to the sum of the original numbers. The least of the original numbers is L . which of the following can be concluded ?      A. L is greater than or equal to 16 
B.12< or equal to L < or qual to 15 
C. 8< or equal to L < or equal to 11
D. 1< or equal to L < or equal to 4

ganeshie8 · Answer

3(L^2 + (L+1)^3 + L) = (3L+1)^2

debpriya · Answer

how ???