Mathematics
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OpenStudy (anonymous):
c*9c need help will medal and fan
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OpenStudy (anonymous):
c * 9c
OpenStudy (anonymous):
@angelg139 help plz
Directrix (directrix):
c * 9c means c times 9 times c
OpenStudy (anonymous):
so it the same
Directrix (directrix):
c times c = what?
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OpenStudy (anonymous):
9
Directrix (directrix):
I need to ask what the instructions are for this problem.
Directrix (directrix):
c times c is not 9
c*c = c^2
OpenStudy (anonymous):
write the product in its simplest form. c * 9c
Directrix (directrix):
And, then 9 times that
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OpenStudy (anonymous):
81
OpenStudy (anonymous):
im so losted
Directrix (directrix):
9 * c^2 = 9 c²
OpenStudy (anonymous):
thx
Directrix (directrix):
You are welcome.
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OpenStudy (anonymous):
so when it is like that you add
Directrix (directrix):
Yes c^1 * c^1 = c^(1 + 1) = c²
OpenStudy (anonymous):
6c * (-7c^6) how do you do this one
Directrix (directrix):
And, then multiply that by 9 to get:
9c²
Directrix (directrix):
Give it a try.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
we add 6 to both sides
Directrix (directrix):
This is not an equation so there are no sides.
OpenStudy (anonymous):
ohhh I feel dum
Directrix (directrix):
6c * (-7c^6) =
6 * (-7) * c * c^6 =
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Directrix (directrix):
What is 6 times negative 7 =
OpenStudy (anonymous):
-42
Directrix (directrix):
Yes
Directrix (directrix):
What is c^1 times c^6 =
OpenStudy (anonymous):
7
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Directrix (directrix):
Not just 7 but what letter raised to the 7th power?
OpenStudy (anonymous):
oh so it c^7
Directrix (directrix):
Correct.
Directrix (directrix):
The final answer is what?
Put the c^7 with the -42
OpenStudy (anonymous):
-42c^7
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Directrix (directrix):
Very good. Correct.
OpenStudy (anonymous):
yay
OpenStudy (anonymous):
can you tonder me on math