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|dw:1457487846220:dw|
does a picture help?
The square is the universe?
B ∩ D = ∅ ⇒ A ∩ C = ∅. this is the part i'm confused about. How do you show a proof for this?
Without a Venn Diagram that is.
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@satellite73
lets pick \(x\in A\) and show that \(x\) is not in \(C\)
okay
since \(x\in A\) we know \(x\in B\) as \(A\subset B\)
therefore, since \(B\cap D=\emptyset\) we know \(x\notin D\)
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and since \(x\notin D\) we know \(x\notin C\) since \(C\subset D\)
therefore, if \(x\in A\) we know \(x\notin C\) making \(A\cap C=\emptyset\)
Ohhh
Should we always prove by choosing an element of a set and see how it relates to others?
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