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What is the solution to y = 0.3x for the replacement set x = {5}?
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@Dani_Rose @Jaynator495
(1.5,5) Since 0.3x5=1.5
\(\bf y=0.3{\color{brown}{ x}}\qquad {\color{brown}{ x}}=\{5\}\implies y=0.3({\color{brown}{ 5}})\)
i can only put one number in each box..
First box= 1.5 Second Box= 5
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The first box can only hold one number the second can only more then 1 number
Oh sorry i got them mixed up 5 for the first box and 1.5 for the second
@MrHirohito
(5 , 1.5) @MrHirohito
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