Can someone help me factor this polynomial? I'm very confused and have tried everything. (Algebra 2)

2x^3-98a^2x+28x^2+98x

Question

Can someone help me factor this polynomial? I'm very confused and have tried everything. (Algebra 2)

2x^3-98a^2x+28x^2+98x

angel_kitty12 · Answer

$$2x^3-98a^2x+28x^2+98x$$ Here is the equation

loser66 · Answer

2 is in common , hence it is out
x is in common,it is out also.
You show me your work

angel_kitty12 · Answer

okay i will try to do so. what i got was $$2x(x^2-49a^2+14x+49)$$

angel_kitty12 · Answer

i got stuck here. I'm this can be simplified more and that this isn't the final answer... @Loser66

angel_kitty12 · Answer

We just found the GCF but haven't factored it. Although, 14 is not factorable by 2

angel_kitty12 · Answer

you cannot square 14

loser66 · Answer

x^2+14x+49= (x+7)^2

loser66 · Answer

See?

angel_kitty12 · Answer

how did you get that?

loser66 · Answer

$x^2+2*7*x+7^2=(x+7)^2$

loser66 · Answer

Formula

loser66 · Answer

If you don't like it, just go backward $(x+7)^2 =(x+7)*(x+7)=x^2+14x+49$

angel_kitty12 · Answer

I'm sorry if i am making this complicated but where did the' a' go? I'm usually very good at this but I just don't get this. I really appreciate you taking your time for me though.

loser66 · Answer

Not yet. YOu must understand this step first

angel_kitty12 · Answer

can you do it step by step for me?

loser66 · Answer

Ok

angel_kitty12 · Answer

I'm really trying to learn this for a test I have soon.

loser66 · Answer

$$2x[(x+7)^2-49a^2]$$
ok then?

angel_kitty12 · Answer

okay that i get. you grouped the first three variable to get (x+7)^2

loser66 · Answer

$49a^2 = (7a)^2$ OK?

angel_kitty12 · Answer

yes

loser66 · Answer

so, $2x[(x+7)^2-(7a)^2]$ ok?

angel_kitty12 · Answer

yes

loser66 · Answer

Do you know that $A^2 - B^2 = (A+B)*(A-B)$?

loser66 · Answer

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