A conductor having charge density sigma is placed perpendicularly to a uniform electric field E and is connected to a spring(of spring constant k) whose other end is fixed. Now the spring is replaced by similar spring having length one third of the original spring.The extension of spring in this position is

Question

samigupta8 · Answer

Electric field is in direction of spring extension

samigupta8 · Answer

@michele_laino

samigupta8 · Answer

I m getting the same extension as i got for original spring.  
I m not getting how will the ans change for spring of diff length..

michele_laino · Answer

let's suppose to have a linear conductor whose charge linear density is $\lambda >0$ and whose length is $L$:
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