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A garage door opener has a power rating of 350 watts. If the door is in operation for 30 seconds, how many joules of energy are used? (Hint: Remember that 1 watt = 1 joule/sec)

a.350 J
b.11.7 J
C.10,500 J
D.0.086 J

Question

will medal
A garage door opener has a power rating of 350 watts. If the door is in operation for 30 seconds, how many joules of energy are used? (Hint: Remember that 1 watt = 1 joule/sec)

a.350 J
b.11.7 J
C.10,500 J
D.0.086 J

hope210 · Answer

@logan13

anonymous · Answer

Power = Rate of work done
P = W/t
Where W = work done, t= time
350/30 = Work done

radar · Answer

Joules and "watt seconds" are equivalent.
Simply multiply the power times the time.