Question

someone rescue me from this........hell X(

Answer 1

in guinea pig, the black coat (B) is dominant over the white coat(b), and the straight hair (H) is dominant over curly hair (h). using a punnett square, complete the cross between a heterozygous black, curly-haired individual and a homozygous straight-haired, white individual. state the parent genotypes, gametes, and the F1 phenotypes and genotypes

Answer 2

Ok, let's first talk about parent genotypes. Can you form the parent genotypes?

Answer 3

i know it's a dihybrid crosses when multiple traits are being transferred to the next generation but how do i go about solving this question?!?!??!

Answer 4

Genotype for heterozygous black, curly-haired individual = ?

Answer 5

well it's going to be......Bh somethhing.. .

Answer 6

Since, it's heterozygous black it should be Bb and for curly it would be hh so genotype will be Bbhh

Answer 7

For other parent?

Answer 8

oh ok and that's for heterozygous right? what about the homozygous??!?!

Answer 9

i think it'll be bbHH?

Answer 10

Homozygous staright and white = bbHH

Answer 11

Yes

Answer 12

Now, simply draw the punnet square

Answer 13

yahhh i have no idea how i got that X"D

Answer 14

ok so it'll go like this let me draw real quick.....:")