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Solve for x if −ax + 3b > 5.
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a) x > the quantity 3 times b minus 5 all over a b) x > the quantity 5 minus 3 times b all over negative a c) x < the quantity 3 times b plus 5 all over a d) x < the quantity negative 3 times b plus 5 all over negative a
@Mehek14
first move 3b to the other side
\[3b/3b>5/3b\]
right?
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no o.o just subtract -ax + 3b - 3b > 5 - 3b -ax > 5 - 3b
then you divide -a on both sides
lol i'm terrible at algebra :/
Wouldn't that make the answer \[x > 5-3b/-a\]
Making the answer B.
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correct :)
Thanks! :D
yw :)
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