Question

Will give medal

Answer 1

4a^2+b^2 if 2a+b=3, ab=1

Answer 2

4a*a+b*b=4a*a+b*b+4a*b-4a*b=(2a)^2+b^2+2*2a*b-4ab=(2a+b)^2-4ab

Answer 3

HINT: \((2a+b)^2=4a^2+b^2+4ab\)

Answer 4

Please include the instructions with posts like this one. Else others have to guess regarding what you want to do.