Question

a tennis ball gone astray rolls across a 3.2m wide deck and off a 1.8m high retaining wall, landing 1.4m from the base of the wall. how long did it take the ball to roll across the deck?

Answer 1

hint:
time \(t\) needed to the ball to reach the Surface, is:
\[\huge 1.8 = \frac{1}{2}g{t^2}\]
where \(g=9.81\) meters/seconds
please solve for \(t\)