Question

Help me please

Answer 1

@imqwerty

Answer 2

im sorry what?!? i dont get it and ive already passes pre algebra

Answer 3

@ilovebmth1234 ^

Answer 4

I need help to solve the equation mainly

Answer 5

i know that the 19^0 is 1 because the 0 exponents is a 1

Answer 6

how can you explain the steps on how you got that so I can know in the futture

Answer 7

oh ok how did you simplifie it?

Answer 8

did the whole equation?

Answer 9

do everything in the parenthesis first remember
P.E.M.D.A.S

P- parenthesis
E- exponents
M- multiplication
D- division
A- addition
S- subtraction

Answer 10

oh right...

Answer 11

I am confused how to solve the first equation in parenthesis though

Answer 12

what about the first parenthesis that is confuseing me

Answer 13

how do you solve this part? : (2^8 ⋅ 5^−5 ⋅ 19^0)^−2

Answer 14

okay im gonna delete all the answers ive done now and just put one big summary of whats going on lol

Answer 15

ok

Answer 16

your answer should be 25

okay well it wont let me do it how i wanted to but this is your answer and just remem

Answer 17

remember the P.E.M.D.A.S

Answer 18

yes

Answer 19

how do you solve the first part though?

Answer 20

which part?

Answer 21

(2^8 ⋅ 5^−5 ⋅ 19^0)^−2

Answer 22

okay so you solve for the exponents first so 2^8 would be 256, 5^-5 would be

0.00032, and 19^0 would be 1 giving you this (256*0.00032*1)^-2 okay?

so now you do whats in the parenthesis so (256*0.00032*1) would = 0.08192

then you take 0.08192 and add the exponent witch makes it 0.08192^-2 then solve that


0.08192^-2 = 149.011611938

Answer 23

oh....... got it

Answer 24

@ilovebmth1234 need help in the fraction part