Two charges each equal to q , are kept at x=-a and x =+a on the x-axis. A particle of mass m and charge q/2 is placed at origin. If this charge is given a small displacement (y a) along the y axis.The net force acting on the particle is proportional to?

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priyar · Answer

@ganeshie8  @agent0smith

priyar · Answer

i solved this.. and got an answer..but it seems to be wrong

priyar · Answer

the net forcewill be 2Fcos (theta)

priyar · Answer

i got F= kq^2/ (2a^2 *  (1+y^2)).. where F is the force bet. q and q/2..
is this correct?

ganeshie8 · Answer

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