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OpenStudy (mahoganie.carson):
What is this?
OpenStudy (cheesecakekitten):
im SORRY.
OpenStudy (mahoganie.carson):
It's ok
OpenStudy (cheesecakekitten):
New question
OpenStudy (mahoganie.carson):
Ok
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OpenStudy (cheesecakekitten):
What are the solutions to the equation?
Transform the polynomial into a perfect square trinomial to solve.
\[x^2 - 14x = 15\]
A. \[(-15, 29)\]
B. \[(-22, 36)\]
C. \[(57, 71)\]
D. \[(-1, 15)\]
OpenStudy (mahoganie.carson):
Sorry i don't know this one do you have anybody else to help you?
OpenStudy (mahoganie.carson):
@jhonyy9 Could you help her i don't know the answer so i can't :)
jhonyy9 (jhonyy9):
this will be more easy to solve it in this way
x^2 -14x =15
x^2 -14x -15 = 0
(x-15)(x+1)=0
do you can solve it now ?
OpenStudy (cheesecakekitten):
I can try....
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