NEED HELP PLEASE
CREATING PUNNETT SQUARES FOR THE FISHER FAMILY There are six people in the Fisher family. Olivia and Marcus are the parents. They have four children: Violet, Nathan, Jonas, and Claudia. Neither Olivia nor Marcus have freckles. What is Olivia's genotype? What is Marcus' genotype? What is the probability that each child has of inheriting freckles? Both Marcus and Olivia are heterozygous for the hairline trait. What is the probability that each of their children could inherit a widow's peak? What is the probability that each of their children could inherit a straight hairline? What is the probability that each of their children could be homozygous dominant for the trait? Neither Marcus nor Olivia can roll their tongues. How many of their children could be born with the ability to roll their tongues? How many of their children could be hybrids? What is the genotype of the whole family? All four children have dimples. What is likely the genotypes of their parents? Do we know with certainty that one of the parents has to have dimples? Both Olivia and Marcus are EE for the earlobe trait. Among their children, what is the ratio of free earlobes to attached earlobes? What percentage of the children are homozygous? Marcus can not detect the bitter taste. Olivia has been found to be able to detect the bitter taste, but she is heterozygous for the trait. What is the probability that each of their children could taste the ptc paper? If Violet can not taste the ptc paper, what is Violet's genotype? Given what you know, how many of the family can taste the ptc paper?
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Welp here it goes.... Wow, this is a big question, but here goes. Freckles q: 1) Since freckles is the dominant phenotype, this means that Olivia must have the recessive phenotype, which is only given by the genotype ff. FF and Ff would both give freckles because, again, freckles is dominant. So any genotype with F_ would give freckles. 2)Same answer as #1. 3) Since they only have f alleles to pass on, both the dad and the mom will pass on one f each to 100% of their children. So all will have genotype ff and no freckles. Hairline q: Since the parents are heterozygous, this means that their genotype has one of each allele to give Hh. (Even though you said they are quadruplets, I'm going to assume they are fraternal (different DNA) b/c otherwise they'd always have the same genotype if they are identical). 1) Okay, so when you do the Punnett square for Hh x Hh, you'll get 1HH:2Hh:1hh. Since widow's peak is dominant, any genotype with H_ gives the widow's peak. So, there are 3 options from the Punnett square, so you'll have 3 of the kids with widow's peak. Theres a 3/4 chance that a child will have widow's peak from these parents. 2) Since straight hairline is recessive, you need hh to get this phenotype and there is only one option. So, there will only be one child with the straight hairline. (1/4 chance). 3) Homozygous dominant means that you have two of the dominant allele, so HH. Since there is only 1 option, there is only one child with this genotype. Tongue q: Since rolling the tongue is a dominant trait and the parents both can't roll their tongues, they must have a homozygous recessive genotype for this to happen (remember in dominance, any genotype with a dominant allele will give the dominant phenotype), so they have tt. 1) Since again they can only pass on t alleles, the kids will all have tt, so no one can roll their tongues. 2) None of them are hybrids because there was no variety in the genotypes or anything. Both parents had tt, so they were same in genotype. 3) She will have tt because of the above stated reasons. Dimples q: Since all four kids have dimples, the dominant phenotype, they must all have the genotype D_ (either Dd or DD). 1) Since Marcus is a hybrid, this means that he had parents that were DD x dd to give him the genotype Dd. Since he has a recessive allele d in his genotype, Olivia must have all dominant alleles to make sure that each child has at least one dominant D. So, she must have the genotype DD. 2) Since she is DD, the dominant alleles will make her have dimples. Earlobe q: 1) Since the parents are EE both, a cross of EE x EE will give EE genotype children. So, all children have EE, this means they all have free earlobes. So the ratio is 100% free to 0% attached earlobes. 2)Homozygous means they have two of the same alleles. Since all of them have EE, 100% of them are homozygous. PTC q: Marcus has genotype bb and Olivia has genotype Bb because she is heterozygous. 1) The cross of bb x Bb gives 1Bb:1bb, So, 1/2 can taste the paper, so 50% can taste. 2) Since Violet can't taste the paper, she must be recessive and have the genotype bb. Since both of the boys can taste, they must have the genotypes Bb. Since 1/2 is already Bb, Claudia must be bb to help create the 50% that can't taste in the kids. 3)So, 2 people out of the family can taste the paper. Even though Olivia has Bb and should be able to taste, she can't. So, only Jonas and Nathan can taste the paper. Pheww... done.. Hope this helps! :) Source(s): http://answers.yahoo.com/question/index;... Try looking through this question and trying it on your own using all the info I gave you before looking at the answer. These are the basic principles to getting Punnett squares and inheritance. There! :D -Angel https://answers.yahoo.com/question/index?qid=20110407150518AABu9W2
THANKS SOOOOOOOO MUCH!!!!!!!!!!!!!!!
I didn't do any thing! I just found it :) But You welcome :D
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