Question

The graph of f(x)=1/x^2-c has a vertical asymptote at x=3. Find c.
Please help with steps on how to solve.

Answer 1

What if I told you that a vertical asymptote happens when the denominator is equal to 0?

\[Denominator=x^2-c\]

X = 3, and you want the denominator = 0, so how should I do the next step?

Answer 2

Would you set the denominator equal to zero?

Answer 3

@FortyTheRapper

Answer 4

Yep, so how would that look?

Answer 5

x^2-c=0
x^2=c
@FortyTheRapper