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MEDAL AND FAN FOR RIGHT ANSWER An image point after a 180° rotation is Z'(9, 2). What were the coordinates of the pre-image point? Z(2, 9) Z(-9, -2) Z(-2, 9) Z(2, -9)
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180 is just basically a half degree turn so the points it is on now is (9, 2)
So first we need to think where (9, 2) is on the grid. It is in the 1st quadrant. Right?
yea
So we turn it around or go back and it is turning across the x axis.
Now when we turn it around, where does it land? Like just turn it around half way.
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It is gonna be in the 4th quadrant. Which answer is in the 4th Quadrant?
d?
Right!
Because when you turn the figure back 180 degrees, it lands on (2, -9)
|dw:1458241892247:dw|
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|dw:1458241936999:dw|
Thanks ILUVSOCCER
|dw:1458242025998:dw|
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