two planes leave an airport at the same time, one flying east, the other flying west. the eastbound plane travels 100 mph slower. they are 4000 mi apart after 5 hr. find the speed of each plane. @janu16

Question

janu16 · Answer

5x + 5(x+100) = 4000
x=350
I defined x as the speed of the slower speed 
so the slower plane has speed of 350 mph 
I defined x+100 as the speed of the faster plane, so 
faster plane goes (350+100) or 450 mph 
check: 
what is 4(330) + 4(430)=4000

janu16 · Answer

slower plane is 350mph
faster plane is 450 mph

janu16 · Answer

@pphalke sorry i took long

janu16 · Answer

@pphalke do you understand that?

anonymous · Answer

rate times time equals distance.
{ 5 west + 5 east = 4000, east = west - 100 } // Solve
$${ east = 350, west = 450 }$$