Question

two planes leave an airport at the same time, one flying east, the other flying west. the eastbound plane travels 110 mph slower. they are 3320 mi apart after 4 hr. find the speed of each plane. @janu16 its the same question just numbers changed

Answer 1

is it the same question but different numbers?

Answer 2

yea they tricked me

Answer 3

so did oyou see the other answer?

Answer 4

I saw it
so far I did 4x+4(x+110=3320 is that right @Janu16

Answer 5

yes

Answer 6

4x + 4(x+110) = 3320
x=360
I defined x as the speed of the slower speed
so the slower plane has speed of 360 mph
I defined x+100 as the speed of the faster plane, so
faster plane goes (360+110) or 470 mph
check:
what is 4(360) + 4(470)=3320

so the slower plane is 360mph
fater plane is 470 mph

Answer 7

i got it. its up there^^

Answer 8

470-360 is 110, not 100 .

Answer 9

i know i made a mistake cause i copied my last answer and forgot to change nubers

Answer 10

could someone help me with a question?

Answer 11

she had a same question but different numbers on her last post so i forgot to chnage that numberr

Answer 12

@pucusana tag me and i will see

Answer 13

\[{5 west + 5 east = 4000, east = west - 100} // Solve\]\[\{\text{east}=350,\text{west}=450\} \]

Answer 14

@robtobey is ur answer right to my question

Answer 15

im right cause he has 4000 and remebr the number chnaged? to 3320?? @pphalke

Answer 16

@robtobey its not 4000 its 3320

Answer 17

@robtobey and its 110 not 100 you made error in the whole problem

Answer 18

I believe that when the problem was first posted the distance apart was 4000 miles.
Was the distance later changed to 3320 miles ?

Answer 19

yea cause these are 2 different problems

Answer 20

she got 2 problems with different numbers so she was confused by your answer

Answer 21

Thank you for the response.

Answer 22

no problem