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complex number question
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is the answer 2
@ganeshie8
@UnkleRhaukus
Use Euler's formula\[\large\boxed{\cos\theta+i\sin\theta=e^{i\theta}}\]
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i did this
\[e ^{\alpha}+e ^{\beta}+e^{\gamma}\]
\[a^{-1}=e^{-i \alpha} \] @kanwal32 use this only
and \[e^{-i \alpha}= \cos \alpha-i \sin \alpha \]
u will find solution
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i give u the answer or no ? @kanwal32
the answer is B
U guys need help here?
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