Question

What is the solution to the system?

Line 1
x y
–2 –4
–1 –1
Line 2
x y
2 3
3 1

( , )

Answer 1

@alivejeremy @Hayhayz

Answer 2

The slope is found by y_{2} -y_{1} / x_{2} - x_{1}
Line 1: y2 is 6, y1 is 4, x2 is 2, x1 is -2
6-4/2- -2= 2/4=1/2

Slope intercept is written as y= mx+b. m is the slope, and b is the intercept (the intercept is the value of y when x is 0). To find out the intercept, we plug in values of y, m and x
4= 1/2(-2) +b
4=-1+b
5=b
The equation for line 1 is y= 1/2x +5
Using the same formulas as above, the equation for line 2 is y= 3x+4
The solution to the system is a point where both lines would meet in the graph, or a set of x and y values that satisfies both equations.
y= 3x+4
y= 1/2x+5
3x+4 = 1/2x+5
3x= 1/2x +5 -4
3x= 1/2x +1
3x-1/2x= 1
2.5x=1
2.5x/2.5=1/2.5
x=0.4
Plug 0.4 into the slope intercept equation

Answer 3

y= 3(0.4) +4
y= 1.2 +4
y=5.2

y= 1/2(0.4) +5
y= 0.2 +5
y= 5.2
The solution is 0.4, 5.2

The other set of lines
Line 1: y= 3x+2
Line 2: y= -2x +7
Solution: 1,5

Answer 4

thx ill tell u if u are correct altho im pretty sure u are ;)

Answer 5

your answer was right

Answer 6

medal me plz

Answer 7

ill medal u dont wrry but can u help meh with 5 more if u have the time to spare

Answer 8

ok

Answer 9

ok first question is

The coordinates below represent two linear equations.

How many solutions does this system of equations have?

Line 1
x y
–3 5
0 4
Line 2
x y
0 4
6 2


A.
0

B.
exactly 1

C.
exactly 2

D.
infinitely many

Answer 10

okay.
so, first you need the slope of both lines. Slope equation is (y2-y1)/(x2-x1)
(Line 1)
2--2/1--1
4/2
2

(Line 2)

Answer 11

(1-10)/(4--2)
-9/6
-3/2

Answer 12

does that mean its a b c or d

Answer 13

the second question is

The coordinates below represent two linear equations.

How many solutions does this system of equations have?

Line 1
x y
–4 5
0 2
Line 2
x y
0 5
4 2


A.
0

B.
exactly 1

C.
exactly 2

D.
infinitely many

Answer 14

it b

Answer 15

for the first or second

Answer 16

first

Answer 17

and the second when ever u are ready

Answer 18

ill just post it on a diff one brb and then ill tag

Answer 19

ok