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Mathematics 7 Online
OpenStudy (anonymous):

Factor the expression. 6x2 + 5x + 1 a. (3x + 1)(2x – 1) b. (3x – 1)(2x – 1) c. (3x – 1)(2x + 1) d. (3x + 1)(2x + 1) 2. Factor the expression. r2 – 49 a. (r + 7)(r + 7) b. (r – 7)(r + 9) c. (r – 7)(r – 7) d. (r – 7)(r + 7)

OpenStudy (janu16):

same as last one so for number 1: Multiply 6 by 1, which is 6. Which two numbers add up to 5 and multiply to 6?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

3 and 2

OpenStudy (janu16):

correct and it add and multiply to 5 and 6 Rewrite 5x as the sum of 3x and 2x 6x^2+3x+2x+1 3x(2x+1)+(2x+1) and we are gonna cancel out 3x so (2x+1)(3x+1) ----final answer so what chocie?

OpenStudy (janu16):

@brandel26

OpenStudy (anonymous):

d

OpenStudy (janu16):

correct and moving on to number 2

OpenStudy (anonymous):

ok

OpenStudy (janu16):

what 2 number gives you 49 whenw you multiply?

OpenStudy (anonymous):

7

OpenStudy (janu16):

correct Rewrite it where a=rand b=7 r2−72 and the formula we are gonna use is difference of square : a2−b2=(a+b)(a−b)

OpenStudy (anonymous):

A?

OpenStudy (janu16):

nope not done yet

OpenStudy (janu16):

the formula is (a+b)(a-b) so we are using 7 so use r and 7 and put it in that pranthseiss

OpenStudy (janu16):

(a+b)(a-b) ----since this is the formula its gonna be (r+7)(r-7) so what chocie?

OpenStudy (anonymous):

D?

OpenStudy (janu16):

yess correct

OpenStudy (janu16):

can i get amedal cause im trying to bring my score up?

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