The diagram shows a section of a bridge between the points A and K. The length of line segment AK is 640 meters. ∆ABC, ∆CDF, and ∆FJK are similar, and 2AC = CF = 2FK. The first pillar, BG, is 20 meters tall. The area of ∆CDF is ___square meters.
@KendrickLamar2014
in order to find the area you need values of "CF" and "DH"... from 2AC = CF = 2FK and the fact that AK = AC+CF+FK ... we should be able to get CF... Also, as the triangles are similar that should help in getting DH given BG is 20m... Does that help ??
Not at all. I'm really bad at this stuff, I'm making a 68 in math models and I can't pass this application to finish. I've failed this I dont know how many times.
lets take it step by step: from 2AC = CF = 2FK and the fact that AK = AC+CF+FK ... we should be able to get CF... Can you explain what you understood from this ?
I dont understand how to do this since we dont have the measurements.
do you agree that AK = AC+CF+FK ???
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