Question

event of one spin of the spinner.
a multiple of 10

A 1/6
B 1/3
C 1/2
D 2/3

Answer 1

The probability of getting a multiple of 10 on one spin is found from:
\[\large P(multiple\ of\ 10)=\frac{number\ of\ multiples\ of\ 10}{total\ number\ of\ numbered\ sectors}\]

Answer 2

Would it be a?

Answer 3

How did you get that?
How many multiples of 10 are on the spinner?
How many numbered sectors are on the spinner?

Answer 4

got it?