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A circle is centered at (2, -5) and has radius 3. Write its equation in standard form. A) (x + 2)2 + (y - 5)2 = 3 B) (x - 2)2 + (y + 5)2 = 3 C) (x + 2)2 + (y - 5)2 = 9 D) (x - 2)2 + (y + 5)2 = 9
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Equation of circle with center \((h, k)\) and radius \(r\). \((x - h)^2 + (y - k)^2 = r^2\)
Replace x with 2, k with -5, and r with 3. What do you get?
(x-2)^2+(y+5)^2=9
That's right :)
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