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OpenStudy (itsmichelle29):
help please medal and fan Solve the equation on the interval left bracket 0 comma 2 pi right parenthesis .[0,2π). 2 cosine 2 x plus StartRoot 3 EndRoot equals 2cos2x+√3=0
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OpenStudy (itsmichelle29):
2cos2x+√3=0
OpenStudy (itsmichelle29):
that is the equation
OpenStudy (mathmale):
You want to find cos 2x first and then find the value of x itself. Start by isolating cos 2x on the left side; subtract sqrt(3) from both sides to accomplish this.
OpenStudy (itsmichelle29):
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