Question

@hartnn

Answer 1

Eccentricity of the hyperbola whose asymptotes are given by 3x+2y-5=0 and 2x-3y-5=0 is :-
A) root2
B) 3/2
C) 2
D) 5/3

Answer 2

\(eccentricity = \sec (\alpha/2)\)

where \(\alpha\) is the angle between 2 asymptotes.

so whats the angle between those 2 lines?

Answer 3

wait !

Answer 4

i got
tan alpha=13/12

Answer 5

@hartnn

Answer 6

:O

Answer 7

those 2 are perpendicular lines
we can easily get that by just looking at the co-efficients

Answer 8

oh !
yeah yeah

Answer 9

so \(\theta = 90\)
sec 45 is your answer

Answer 10

but where is my mistake ?