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Mathematics 19 Online
OpenStudy (shaleiah):

Medal for help with polygons

OpenStudy (shaleiah):

OpenStudy (vishweshshrimali5):

See for similarity we need the ratio of corresponding sides to be equal..

OpenStudy (shaleiah):

Alright

OpenStudy (vishweshshrimali5):

For example consider this figure... |dw:1458658914700:dw| Triangles ABC and PQR are similar so: \(\frac{AB}{PQ} = \frac{BC}{QR} = \frac{AC}{PR}\)

OpenStudy (vishweshshrimali5):

Any doubt till now?

OpenStudy (vishweshshrimali5):

Now, can you write a similar expression for the given figure?

OpenStudy (shaleiah):

i'll try

OpenStudy (vishweshshrimali5):

Great :)

OpenStudy (shaleiah):

2(x-6)/28=15/9

OpenStudy (vishweshshrimali5):

Great!!

OpenStudy (vishweshshrimali5):

Just one thing.. that should be 2x - 6 not 2(x-6)

OpenStudy (vishweshshrimali5):

So we have this equation... \[\cfrac{2x - 6}{28} = \cfrac{15}{9}\] Can you solve this to obtain x ?

OpenStudy (shaleiah):

26.3333

OpenStudy (vishweshshrimali5):

Great!! That's right :)

OpenStudy (shaleiah):

Thank you so much for your help!

OpenStudy (vishweshshrimali5):

Your welcome :)

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