Two blocks are kept one over another on the horizontal rough surface .If the two blockd are given a horizontal velocity towards right, and acm be thr subsequent acceleration of COM of system of blocks then acm equals (ma=2mb) .
(coefficient of friction between horizontal surface and block B is 0.2
And that between A and B is 0.3.)

Question

Two blocks are kept one over another on the horizontal rough surface .If the two blockd are given a horizontal velocity towards right, and acm be thr subsequent acceleration of COM of system of blocks then acm equals (ma=2mb) .
(coefficient of friction between horizontal surface and block B is 0.2
And that between A and B is 0.3.)

samigupta8 · Answer

@ganeshie8 @irishboy123

anonymous · Answer

What is acm and com 
What is the question then

samigupta8 · Answer

Acm is acceleration of centre of mass
And COM is short form of centre of mass

anonymous · Answer

Now the question is to find what?

samigupta8 · Answer

Acm??

irishboy123 · Answer

|dw:1458735551609:dw|

$F_{sys} = 3m a_{sys} = - (0.2)(3m)g, \qquad  a_{sys} = -0.2g$