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Where is the location of the vertex of the parabola on a coordinate grid? y = x^2 + 2x + 3 A. Above the x-axis B. On the y-axis C. Below the x-axis D. On the x-axis
i thought it was free
"Easy", not "Free".
so bassicy it would be x1 = −2 − √ 22 − 4×1×3 2×1 = −2 − 2 × √ 2 i 2 ≈ −1 − 1.414214i x2 = −2 + √ 22 − 4×1×3 2×1 = −2 + 2 × √ 2 i 2 ≈ −1 + 1.414214i
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@usercode3rror that's not one of the answer choices. Did you read the question wrong?
no ik but hold
x+=+3 or x+=+-1 Simplify.
does that help brownie
the points of ur porabla is x+=+3 or x+=+-1 Simplify.
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