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OpenStudy (johnnewman):
What is the interquartile range of the data?
100, 120, 130, 188, 196, 220, 265, 300
A.
200
B.
117.5
C.
242.5
D.
145
https://www.mathsisfun.com/data/images/interquartile-range.gif
8 years ago
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OpenStudy (kayders1997):
Will first you need to find Q1 Q2 and Q3
8 years ago
OpenStudy (kayders1997):
And when you do these you have to find Q2 first, how do you do that?
8 years ago
OpenStudy (johnnewman):
The three quartiles Q1, Q2, and Q3 divide the data into four “equal” parts. About 25% of the data falls at or below Q1, 50% of the data falls at or below Q2, and 75% falls at or below Q3. To find the quartiles: 1.
Section 2.5, Measures of Position
8 years ago
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OpenStudy (kayders1997):
I know how I'm asking you :)
8 years ago
OpenStudy (johnnewman):
yes
8 years ago
OpenStudy (kayders1997):
Okay so what do you get for your Q2
8 years ago
OpenStudy (johnnewman):
130 and 188
8 years ago
OpenStudy (kayders1997):
hmmmmm?
8 years ago
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OpenStudy (kayders1997):
Q2 is the median number
8 years ago
OpenStudy (johnnewman):
192
8 years ago
OpenStudy (kayders1997):
Good now you have to split this up into two sections for the Q1 and Q3
8 years ago
OpenStudy (johnnewman):
how
8 years ago
OpenStudy (kayders1997):
So start on the left side the smallest number though188
8 years ago
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OpenStudy (kayders1997):
Find the median on those numbers
8 years ago
OpenStudy (johnnewman):
100,120,130 and 188
8 years ago
OpenStudy (johnnewman):
120 and 130 so i need to add both and / by 2 right
8 years ago
OpenStudy (kayders1997):
Yes
8 years ago
OpenStudy (johnnewman):
125
8 years ago
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OpenStudy (kayders1997):
Yes so that is your Q1
8 years ago
OpenStudy (kayders1997):
Now you need to do the right side from 188 to the highest number so your splitting these numbers up by where the median is
8 years ago
OpenStudy (johnnewman):
188,196,220,265 and 300 right
8 years ago
OpenStudy (johnnewman):
its 220
8 years ago
OpenStudy (kayders1997):
My bad it's 196
8 years ago
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OpenStudy (kayders1997):
Where you need to start, the right of the median
8 years ago
OpenStudy (johnnewman):
196
8 years ago
OpenStudy (kayders1997):
Yes so you need to start there and go to the highest number than find the median there
8 years ago
OpenStudy (johnnewman):
so i got 220 and 265 so add both and / by 2 right
8 years ago
OpenStudy (kayders1997):
Yes
8 years ago
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OpenStudy (johnnewman):
242.5
8 years ago
OpenStudy (johnnewman):
its c right
8 years ago
OpenStudy (kayders1997):
Yes that is your Q3 now inner quartile range says subtract the 3rd inner quartile by the 1st inner quartile so Q3-Q1
8 years ago
OpenStudy (kayders1997):
No
8 years ago
OpenStudy (johnnewman):
its b
8 years ago
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OpenStudy (kayders1997):
Yes :)
8 years ago
OpenStudy (johnnewman):
thank kayders1997
8 years ago
OpenStudy (kayders1997):
You're welcome :) JohnNewman
8 years ago
OpenStudy (johnnewman):
i have medal you
8 years ago
OpenStudy (kayders1997):
Thanks :)
8 years ago
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OpenStudy (kayders1997):
And I have medaled you for your effort
8 years ago