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Mathematics 58 Online
OpenStudy (johnnewman):

What is the interquartile range of the data? 100, 120, 130, 188, 196, 220, 265, 300 A. 200 B. 117.5 C. 242.5 D. 145 https://www.mathsisfun.com/data/images/interquartile-range.gif

OpenStudy (johnnewman):

look at this https://www.mathsisfun.com/data/images/interquartile-range.gif

OpenStudy (kayders1997):

Will first you need to find Q1 Q2 and Q3

OpenStudy (kayders1997):

And when you do these you have to find Q2 first, how do you do that?

OpenStudy (johnnewman):

The three quartiles Q1, Q2, and Q3 divide the data into four “equal” parts. About 25% of the data falls at or below Q1, 50% of the data falls at or below Q2, and 75% falls at or below Q3. To find the quartiles: 1. Section 2.5, Measures of Position

OpenStudy (kayders1997):

I know how I'm asking you :)

OpenStudy (johnnewman):

yes

OpenStudy (kayders1997):

Okay so what do you get for your Q2

OpenStudy (johnnewman):

130 and 188

OpenStudy (kayders1997):

hmmmmm?

OpenStudy (kayders1997):

Q2 is the median number

OpenStudy (johnnewman):

192

OpenStudy (kayders1997):

Good now you have to split this up into two sections for the Q1 and Q3

OpenStudy (johnnewman):

how

OpenStudy (kayders1997):

So start on the left side the smallest number though188

OpenStudy (kayders1997):

Find the median on those numbers

OpenStudy (johnnewman):

100,120,130 and 188

OpenStudy (johnnewman):

120 and 130 so i need to add both and / by 2 right

OpenStudy (kayders1997):

Yes

OpenStudy (johnnewman):

125

OpenStudy (kayders1997):

Yes so that is your Q1

OpenStudy (kayders1997):

Now you need to do the right side from 188 to the highest number so your splitting these numbers up by where the median is

OpenStudy (johnnewman):

188,196,220,265 and 300 right

OpenStudy (johnnewman):

its 220

OpenStudy (kayders1997):

My bad it's 196

OpenStudy (kayders1997):

Where you need to start, the right of the median

OpenStudy (johnnewman):

196

OpenStudy (kayders1997):

Yes so you need to start there and go to the highest number than find the median there

OpenStudy (johnnewman):

so i got 220 and 265 so add both and / by 2 right

OpenStudy (kayders1997):

Yes

OpenStudy (johnnewman):

242.5

OpenStudy (johnnewman):

its c right

OpenStudy (kayders1997):

Yes that is your Q3 now inner quartile range says subtract the 3rd inner quartile by the 1st inner quartile so Q3-Q1

OpenStudy (kayders1997):

No

OpenStudy (johnnewman):

its b

OpenStudy (kayders1997):

Yes :)

OpenStudy (johnnewman):

thank kayders1997

OpenStudy (kayders1997):

You're welcome :) JohnNewman

OpenStudy (johnnewman):

i have medal you

OpenStudy (kayders1997):

Thanks :)

OpenStudy (kayders1997):

And I have medaled you for your effort

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