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Microsoft offers its employees one of three pension splans, A, B, or C. Past history shows that 70% of employees choose plan A, 20% choose plan B, and 10% choose plan C. Also, 60% of those who choose plan A are married, 20% of those who choose plan B are married, and 60% of those who choose plan C are married. If a married employee is selected at random, what is the probability the employee is in plan A?
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i think the answer is 0.81
Baye's theorem. \(\dfrac{0.7\times 0.6 }{0.7\times0.6+ 0.2\times 0.2+0.1\times 0.6}\)
you're correct :)
thakn you for helping
welcome ^_^
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